If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2=34x-24
We move all terms to the left:
5x^2-(34x-24)=0
We get rid of parentheses
5x^2-34x+24=0
a = 5; b = -34; c = +24;
Δ = b2-4ac
Δ = -342-4·5·24
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-26}{2*5}=\frac{8}{10} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+26}{2*5}=\frac{60}{10} =6 $
| 6m=112.75–18+8.75 | | 3(x+2)+0.5x=41 | | x^2-25x-113.8=0 | | 7m-1=-9+8m | | 9=3(5x–2)= | | 0.27-x/x=0.179 | | 8b=;b=6 | | -w=6=-2 | | 6x²+12=18 | | 12+5+4=a | | –w+6=–2 | | 1/9n=10 | | 6-2p=8.8 | | -2(x-8)+4x=-13 | | -4x+25=85 | | 39x-2(x+5)=2x+4(4x) | | 318=n=143 | | 2x-15+33=90 | | 182-x=38 | | 4(b-28)=12b-120 | | –10j−9(–3j+10)=3j−10−6j | | r/2-1.54=1.46 | | 3(2m+.7)=-5(6+m) | | 6-u=-2.4 | | 4x-4.2=6.4 | | N-247=605-(4x208) | | m+5÷-2=1 | | 3r-3=r+5 | | –9.2(8x–4)+0.7(2+6.3x=) | | 56y-16=236 | | (5x-1)×(2x+2)=68 | | (1/16)^3x=64^x-4 |